2450+25x+x^2=130x

Solution for 2450+25x+x^2=130x equation:

2450+25x+x^2=130x

We move all terms to the left:

2450+25x+x^2-(130x)=0

We add all the numbers together, and all the variables

x^2-105x+2450=0

a = 1; b = -105; c = +2450;
Δ = b2-4ac
Δ = -1052-4·1·2450
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-35}{2*1}=\frac{70}{2}
=35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+35}{2*1}=\frac{140}{2}
=70
$